Delivery time for all food orders at a restaurant during lunch hr are normally distributed…QNT 275

Quick Tutorial – Solving for Mean and Standard Deviation

Delivery time for all food orders at a restaurant during lunch hr are normally distributed with a mean of 8.1 min and SD of 4.6 min let x bar be the mean delivery time for a random sample of 30 orders. Calculate the mean and SD of x bar

Solving for Standard Deviation

Standard deviation can be solved by dividing the population SD by the square root of the population, like so:

x-bar std = 4.6 / sqrt(30)

x-bar std = 0.84

Solving for the  Sample Mean

The sample mean is going to be identical to the population mean of 8.1. That  was easy, lets move on the standard deviation.

x-bar mean = 8.1 min

The standard of error would be 0.153

 
  • Student: Anonymous
  • Textbook: Statistics
  • Course: QNT 275
 
 

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